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second year essay

Post Icon Posted: Submitted by richardhp on 14 February 2008 - 2:15pm.

Joined: 2007-10-01
Posts: 63

I'm doing my essay on quaternions but I'm struggling to find material on them that isn't on Wikipedia.
Does any one know of any interesting theorems that I could look up. It would be a great help.

cheers.

Post Icon Posted: 14 February 2008 - 3:20pm

Joined: 2006-10-05
Posts: 534

I could loan you the excursions sheet we had to do on this, but that's all i can really suggest. I take it searching the library didn't work.

Have you checked the Wiki references at the bottom of the page?

Post Icon Posted: 14 February 2008 - 3:22pm

Joined: 2006-10-01
Posts: 370

Sadly, quaternions as a number system are rather disappointing:

Does any one know of any interesting theorems that I could look up

The sad truth is that there aren't any, at least in the complex number "holomorphic=analytic=conformal=awesome" type way (see 'quaternionic conformality' thread for my own shuddering disappointment on the matter). But a good line of extension lies in the world of lie groups: SU (2) the special unitary group in 2 dimensions (a sort of complex orthogonal matrix group)is isomorphic to the unit quaternions under multiplication and is a gateway to a world of awesome lie based maths.

Talk about what a lie group is, manifolds, group actions etc. Guaranteed first. Plus damn interesting.

Though if youre hooked on $ \mathbb{H} $ because it's a 'number system' then there is a theorem that states that $ \mathbb{H} $ and $ \mathbb{C} $ are the only rings containing the reals- it's a super hot theorem (can't remember the name though) but it's pretty hardcore. Anyone know the name?

Post Icon Posted: 14 February 2008 - 4:06pm

Joined: 2007-10-03
Posts: 245

Frobenius theorem perhaps ?

And yes, Quaternions are disappointing, nothing like the magnificence of complex numbers.

Post Icon Posted: 14 February 2008 - 4:26pm

Joined: 2007-10-01
Posts: 63

yeah, already got that one but thanks anyway. i'll focus more on group theory in that case, it's mainly what we're studying in algebra now anyway.

thanks for the help.

Post Icon Posted: 15 February 2008 - 1:19pm

Joined: 2007-10-04
Posts: 186

Got to agree with Xedi, there's good reasons why people don't bother with them much these days.

Post Icon Posted: 15 February 2008 - 2:14pm

Joined: 2007-10-03
Posts: 245

Well no, they're still really worth studying and bothering with, there's lots of interesting things going on there, and they really help in many situations.
Just that they aren't as beautiful as you would think they would be, seeing how complex numbers work great.

Post Icon Posted: 17 February 2008 - 10:52pm

Joined: 2007-03-03
Posts: 122

I'm classifying some finite simple groups for mine, and I would appreciate a point in the right direction as regards books. I'm not sure if Dave McCormick is a regular forum checker, but if anyone knows what books he's been using for this, I'd love to know.

Post Icon Posted: 18 February 2008 - 12:36pm

Joined: 2007-10-01
Posts: 63

"Got to agree with Xedi, there's good reasons why people don't bother with them much these days."

Thanks for you 'help'. I'm well aware that quaternions aren't at the cutting edge of research but that doesn't diminish their historical significance, or stop them being interesting. Maybe you could leave trolling to the forums that aren't designed specifically for academic support.

Post Icon Posted: 18 February 2008 - 6:33pm

Joined: 2006-08-31
Posts: 676

We did something very cool with Quarternions in Algebraic Topology today, I'll post it later if I have time, or Tom can.

Post Icon Posted: 18 February 2008 - 7:42pm

Joined: 2006-10-01
Posts: 370

Yeah, 'twas awesome, a sort of converse to the frobenius theorem. Won't spoil it now cos I want to do a bit of it at [Dg] tonight. But yeah will post the details later...

Post Icon Posted: 19 February 2008 - 1:09am

Joined: 2007-10-04
Posts: 186

Trolling :-o The Frobenius theorem is a brilliant result, and they are historically important. They led to the development of a lot of the vector algebra today. It just seems that things get less interesting as you extend further beyond complex numbers. With the loss of associativity and commutitivity they become harder to work with and it seems that their main interest lies in physics. They do seem damn interesting (and are hence a fertile subject for 2nd year essay), it's just they seem a bit limited by their own nature.

edit: Errr, perhaps I should have posted the post in full first time. I just didn't expect many people would be online.

Post Icon Posted: 19 February 2008 - 1:16am

Joined: 2007-03-03
Posts: 122

Stop it. If it helps, go to this site which gives good advice on forum etiquette:

beingniceonline

Post Icon Posted: 19 February 2008 - 1:22am

Joined: 2006-08-31
Posts: 676

getting a bit off topic, please be nice, and start a new thread if you want to discuss something new.

Post Icon Posted: 19 February 2008 - 1:31am

Joined: 2007-03-03
Posts: 122

I'll have to come clean: the above link was supposed to be a RickRoll, but it didn't work. I have yet to fully understand the subtleties of this trolling lark. I'll stop now, Steven's right.

Post Icon Posted: 19 February 2008 - 2:18am

Joined: 2006-10-01
Posts: 370

Anyway- the converse to frobenius theorem...

The idea is that you prove frobenius using the fact that a normed division algebra $ R $ containing $ \mathbb{R} $ immediately yields a normed vector space structure over $ \mathbb{R} $ (just forget about multiplication by anything non-real and the vector space axioms just fall out). Armed with this you construct an n-1 dimensional sphere (assuming your vector space is n dimensional) by way of $ S^{n-1} :=\{x \epsilon R | \vert x\vert=1\} $ and fluff out an inner product (usually :=re (v.u*) - where u* is the conjugate of u).

Using this we can costruct n-1 linearly independent vector fields on $ S^{n-1} $. We do so thus: choose a basis of the imaginary parts of $ R $ (that is those orthogonal to $ \mathbb{R} $) $ \{e_1, e_2 ... e_{n-1} \} $ and suppose $ x \epsilon S^{n-1} $ then we have $ V_i(x):=e_ix $ for each i. Each $ V_i $ now defines a vector field since $ e_ix $ is orthogonal to x and hence tangent to the sphere (all quite easy to check), also (if you chose your original basis to be orthogonal this is much easier using inner product) we see that the $ V_is $ are linearly independent.

And by a result in topology the number of linearly independent vector fields on $ S^{n-1} $ is only n-1 for 1,3 and 7- these correspond to $ \mathbb{C} $,$ \mathbb{H} $ and $ \mathbb{O} $ respectively -$ \mathbb{O} $ being the octonions. Thus these are the only possibles.

Another way of looking at this is as a converse to the hairy ball theorem- that states there is no continuous non vanishing vector field on $ S^{n} $ for even n. Using $ \mathbb{C}^n:=\{(z_1,z_2...z_n)| z_i\epsilon \mathbb{C} \} $ as our vector space we have an inner product as defined above (but with a dot product in place of multiplication and conjugation componentwise) and hence a norm and a 2n-1 dimensional sphere.

We now have for $ v \epsilon S^{2n-1} $, $ V(v):=iv $ which does the job nicely as above...

Now for any $ S^{m}=S^{4n-1} $ we may apply the above ideas (but with i,j and k in place of the i to give 3 guaranteed linearly independent vector fields.

Now for any $ S^{m}=S^{8n-1} $, the octonions give us seven...

By this method we can completely classify linearly independent vector fields on $ S^{n} $ for n<15- after which point, things get complicated (clifford algebras apparently)... Which is awesome.

Get yourself a vector field today!

Any questions?

Post Icon Posted: 19 February 2008 - 4:27am

Joined: 2006-11-02
Posts: 811
I'll have to come clean: the above link was supposed to be a RickRoll, but it didn't work. I have yet to fully understand the subtleties of this trolling lark. I'll stop now, Steven's right.
Trolling 101: never use "www.yougotrickrolled.com" or anything similar, YouTube is far better. I didn't fall for your rickroll because I saw what it linked to in the status bar.

P.S. Sorry. :p
Post Icon Posted: 19 February 2008 - 2:40pm

Joined: 2007-10-04
Posts: 186

Better yet, use a site which re-directs links. On topic though, I like the sketch proof, it's pleasingly... short.

Post Icon Posted: 21 February 2008 - 6:53pm

Joined: 2007-10-01
Posts: 63

i'd quite like to practise my presentation at a discussion group sometime. if we can get 3 or 4 people to do it on the same night that would pretty much fill up the time.

i was hoping for next thursday at the earliest, since i haven't actually written it yet. anyone else interested?

Post Icon Posted: 21 February 2008 - 7:35pm

Joined: 2007-03-03
Posts: 122

Good idea, and I would definitely do the same were it not for the fact that my essay is on the same topic as one of Dave McCormick's discussion groups. You reckon you can find another 3 or 4 people?

Post Icon Posted: 21 February 2008 - 7:52pm

Joined: 2006-10-05
Posts: 534

I also have a similar problem with the Dave $ M^c $Cormickness. Also the I-haven't-chosen-a-title-yet-ness.

Post Icon Posted: 22 February 2008 - 4:14am

Joined: 2006-11-02
Posts: 811

I'll turn up too, though I've done nothing at all yet. When is the real presentation supposed to be?

Post Icon Posted: 22 February 2008 - 1:46pm

Joined: 2006-10-05
Posts: 534

Mine is in week 9 but it is up to your tutor when it is.

Post Icon Posted: 24 February 2008 - 6:00pm

Joined: 2007-10-01
Posts: 63

well i know someone else who wants to do one too, i might be able to persuade another person as well. including cosmin that should be enough entertainment for one evening.

Post Icon Posted: 24 February 2008 - 6:10pm

Joined: 2006-11-02
Posts: 811

Cool. If I don't have anything by then I'll just practice my excursions presentation. :D

Post Icon Posted: 24 February 2008 - 7:27pm

Joined: 2007-10-01
Posts: 63

i have a couple of questions with regards to frobenius theorem.
firstly, what do you mean by linearly independant vector fields, and which result from topology allows you to make the claim required to finish the first proof, i'd like to reference it in my essay even if i don't prove it there.

thanks

Post Icon Posted: 25 February 2008 - 7:03pm

Joined: 2006-10-01
Posts: 370

A vector field may be considered as a function N from a manifold to its tangent space at that point- i.e. taking a point and sending it to a point on the hyperpane tangent to the manifold at that point. For a vector v to be in such a tangent plane say $ T_x(S^n) $ is clearly the same as saying <(v-x),n>=0 (where n is the normal to the manifold), but for $ S^n $ this reduces to <(v-x),x>=0 (since x is normal to $ S^n $ at x- differentiate and try for yourself).

Now linear independence of vector fields $ \{ M_i \} $ is just the statement that for all x$ \epsilon S^n $ $ \{ M_i(x) \} $ is linearly independent. Notice particularly that if $ \{ M_i(x) \}=\{ N(x) \}={0} $ for some x then we have linear dependence vacuously (thus the vanishing vetor fields for $ S^n $ n even which the hairy ball theorem shows are the only ones- do not count as L.I.)

To prove the result we need a lemma saying "if we can do linear independence- we can do orthonormality"- which is much like one from linear algebra, but a little tougher since we must keep continuity satisfied.

From here we realise that we need a function taking orthonormal bases to orthonormal bases- this is just the action of the clifford group, the set of invertible elements of the clifford algebra under multiplication (see clifford algebras on wikipedia or come to me for a chat for details). We see where this group can act and to what degree and get an elementary formula for the number of linearly independent vector fields on $ S^n $. [Can't find this A.T.M. but anyone who's been taking algebraic topology should have it (post now or forever hold your peace)]

This is then equal n only for n= 1,3,7. But if we had a normed division algebra of any other dimension m, then we would get the number of L.I. vector fields on $ S^{m-1}=m-1 $ as above. 7 we deal with separately- I don't know how...

But yeah apparently (after some research) not a topological result. But one in the field of topology. Apparently this is best dealt with in a paper by Eckmann, which I thoroughly intend to find and read soon...

Hope that helps...

Post Icon Posted: 18 April 2008 - 10:40am

Joined: 2007-10-01
Posts: 63

I'm pretty sure I'd have to reference something like this so what kind of book would I find a proof of this nature, or in fact could you just post the name of a book so I can quote it that would be great.