Posted: Submitted by Newtonswig on 9 November 2007 - 1:56pm. |
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Joined: 2006-10-01
Posts: 427 |
Sorry all, the path metric function for our punctured disc should have been:
You will recall that we sincerely hoped our form invariant under indeces, we note that any non trivial linear combination of these would give us non zero roots, so we need only worry about poincare isometries of the form , so
Hence our differential form is invariant under indeces as required. Er... tada!... |
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